若串S1=‘ABCDEFG’, S2=‘9898’ ,S3=‘###’,S4=‘012345’,执行concat(replace(S1,substr(S1,length(S2),length(S3)),S3),substr(S4,index(S2,‘8’),length(S2)))其结果为( )
选项:
A:ABC###G0123;
B:ABC###G1234;
C:ABCD###2345;
D:ABC###01234
发布时间:2024-03-30 23:28:32