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相关试题
- 1.下面程序的输出结果为：import re def double(matched): value = int(matched.group('value')) return str(value * 2) s = 'ABC123G4HFD567' print(re.sub('(?P[value]\d+)', double, s))
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2.#include
int main ( ) {int value1 = 5, value2 = 15；int * mypointer；mypointer = &value1；*mypointer = 10；mypointer = &value2；*mypointer = 20；cout << value1 << " " << value2；return 0；}程序执行后，value2的值为____。 - 3. 单选题Which of the following statements will convert a string s into a double value d? ( ) 选项： A:d = (Double)parseDouble(s); B:d = (new Double(s)).doubleValue(); C:d = (Double)valueOf(s).doubleValue(); D:All of the above.
- 4.Read the following program:int fun1(double a) { return a*=a;}int fun2(double x,double y){double a=0,b=0;a=fun1(x); b=fun1(y); return (int)(a+b);}if w is a variable of type double, what is the value of w, after executing the statement w=fun2(1.1,2.0);? 选项： A:5.21; B:5; C:5.0; D:0.0
- 5.下面程序运行的结果是：第一行 ，第二行 。 class CCircle { protected double radius; public CCircle(double r) { radius=r; } public void show() { System.out.println("Radius="+radius); } } public class CCoin extends CCircle { private int value; public CCoin(double r, int v) { super(r); value=v; } public void show() { System.out.println("Radius="+radius+" Value="+value); } public static void main(String] args) { CCircle circle=new CCircle(2.0); CCoin coin=new CCoin(3.0,5); circle.show(); coin.show(); }
- 6.在C#程序中，定义如下方法，下面选项中（A ）错误的实现对该方法的方法重载。public string Do(int value,string s){//省略代码}选项： A:public int Do(int value,string s){//省略代码}; B:public string Do(string s,int value){//省略代码}; C:public void Do(string s,int value) {//省略代码}; D:public void Do(){{//省略代码}}
- 7.Suppose your method does not return any value, which of the following keywords can be used as a return type?选项： A:void; B:int; C:double; D:None of the above
- 8.Suppose your method does not return any value, which of the following keywords can be used as a return type? 选项： A:void; B:int; C:double; D:None of the above
- 9.以下程序运行后输出结果是（ ）。 选项： A: 输出结果为：value is 99.9 B: 输出结果为：value is 9 C: 输出结果为：value is 9.0 D: 编译错误
- 10.请读程序:#include int f(char s[]){int i=0,p=0;while(s[i++]!='\0')p++;return(p);}void main(){char str[10]="ABCDEF";printf("%d\n",f(str));}上面程序的输出结果是
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11.以下程序执行后的输出为：using namespace std;#include
double f1(double x){ return 1.0/x;}double f2(double x){ return x*x;}int main(){ int i=3; double (*f[2])(double)={f1,f2}; cout< -
12.下面程序的输出结果是_______。#include
double func(int x, int y, int z);int main(void){ double x; int a=3, b=4, c=5; x = func(a, b, c); printf("%f", x); return 0;}double func(int x, int y, int z){ double t; t = x % y * z; return t;}选项： A:3 B:3.000000 C:15 D:15.000000 - 13.The double-declining balance method is applied by (1) computing the asset's straight-line depreciation rate, (2) doubling it, (3) subtracting salvage value from cost, and (4) multiplying the rate times the net value.选项： A:正确; B:错误
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14.下面程序的输出结果是_______。#include
double func(int x, int y, int z);int main(void){ double x; int a=3, b=4, c=5; x = func(a, b, c); printf("%f", x); return 0;}double func(int x, int y, int z){ double t; t = x % y * z; return t;}选项： A:15.000000 B:3.000000 C:3 D:15 - 15.以下不是对Do方法重载的是( )。 public string Do(int value,string s){//省略代码} 选项： A、public int Do(int value,string s){//省略代码} B、public string Do(string s,int value){//省略代码} C、public void Do(string s,int value) {//省略代码} D、public void Do(){//省略代码}
- 16.请说出下面程序中【代码1】和【代码2】的输出结果，以空格隔开。 interface A { double f(double x, double y); } class B implements A { public double f(double x, double y) { return x * y; } int g(int a, int b) { return a + b; } } public class Main { public static void main(String args]) { A a = new B(); System.out.println(a.f(3, 5)); //【代码1】 B b = (B) a; System.out.println(b.g(3, 5)); //【代码2】 } }
- 17.下列程序的输出结果是：def f1 (my_dict): temp = 0 for value in my_dict.values(): temp = temp + value return tempa_dict={'bill':1,'rich':2,'fred':10,'walter':20}print f1(a_dict)
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18.有如下程序#include
int sub(double a, double b){ return (int)(a - b);}main() { printf("%d", sub(3.8, 2.1));}程序运行后的输出结果是（ ）。选项： A:2.0 B:1.7 C:2 D:1 - 19.如果程序运行时从键盘输入“1.234”，下面程序的运行结果是（ ）。try: a=int(input("a number:")) 1 / a except ZeroDivisionError : print("division by zero!") except ValueError: print("value is not an integer!")else: print("That went well!") finally: print("Cleaning up.")选项： A:value is not an integer!Cleaning up.; B:division by zero!Cleaning up.; C:That went well!Cleaning up.; D:value is not an integer!
