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相关试题
- 1.p是指向PERSON类对象的指针，则通过p访问公有成员函数show()的方法是。 选项： A、p.show(); B、p->;show(); C、(*p).show(); D、(*p)->;show();
- x), ( p)->x,*p->y);p =2;printf("%d,%d\n",(p->x), (*p->y));}">2.以下程序的运行结果是________________。# include"stdio.h"struct st{int x；int *y；}*p；void main(){int dt[4]={ 10,20,30,40 };struct st aa[4]={50,&dt[0],60,&dt[1],70,&dt[2],80,&dt[3]},*p=aa;printf("%d,%d,%d \n", (p->x), ( p)->x,*p->y);p =2;printf("%d,%d\n",(p->x), (*p->y));}
- 3.设类Myclass中有公有成员函数Show()，并有以下定义： Myclass obj,*p=obj; 下列语句错误的是： 选项： A、obj.Show() B、obj.Myclass::Show() C、p->Show() D、p.Show()
- 4.请阅读下面的程序,写出程序的运行结果。 class Person { String name; int age; public Person() { System.out.println(“Person()”); } public Person(String n, int a) { name = n; age = a; } public void show() { System.out.println(name + “---“ + age); } } public class Test { public static void main(String[] args) { Person p = new Person(); p.show(); Person p2 = new Person(“林青霞”, 27); p2.show(); } }
- 5.给定Java代码如下所示，在1处新增下列（ ）方法，是对show()方法的重载。public class Test{ public void show(int x, int y, int z) { } //1}选项： A:public int show(int x, int y, float z){return 0;}; B:public int show(int x, int y, int z){return 0;}; C:protect void show(int x, int z, int z){}; D:public void show(int z, int y, int x){}
- 6.给定Java代码如下所示，在1处新增下列（ ）方法，是对show()方法的重载。public class Test{ public void show(int x, int y, int z) { } //1} 选项： A、public int show(int x, int y, float z){return 0;} B、public int show(int x, int y, int z){return 0;} C、protect void show(int x, int z, int z){} D、public void show(int z, int y, int x){}
-
7.观看以下程序:class point{public:void show() {cout<<”point”<
- 8.有函数声明void show(int *arr,int n);有变量,int a,arr[10],*p=arr;对该函数调用正确的是____选项： A:show (a,10)； B:show (a,arr,10)； C:show (arr,10); D:show (*p,10);
-
name,p->num);printf("%s %d
",p->name,p->num);return 0;}
">9.有以下程序#include
#include struct STU{ char name[10];int num;};void f(char *name, int num){ struct STU s[2]={{"SunDan",20044},{"Penghua",20045}};num =s[0].num;strcpy(name,s[0].name);}int main(void){ struct STU s[2]={{"YangSan",20041},{"LiSiGuo",20042}},*p;p=&s[1];f(p->name,p->num);printf("%s %d ",p->name,p->num);return 0;} - 10.请阅读下面的程序，程序的运行结果是（）。 Class Person { String name; int age; public Person() {} public Person(String n, int a) { name = n; age = a; } public void show() { System.out.print(name + "---" + age +" "); } } Public class Test { public static void main(String] args) { Person p1 = new Person(); p1.show(); Person p2 = new Person("周星驰", 27); p2.show(); } }1分 选项： A:null---0周星驰---27 B:null---27周星驰---27 C:周星驰---0null---27 D:周星驰---27null---27
- x ); printf("%d ", (++p)->x); printf("%d ", ++( *p->y));} 选项：102020|506011|516011|203040">11.下面程序的输出结果为struct st{ int x; int *y;} *p;int dt[4]={10,20,30,40};struct st aa[4]={ 50,&dt[0],60,&dt[1],70,&dt[2],80,&dt[3] };main(){ p=aa; printf("%d ", ++p->x ); printf("%d ", (++p)->x); printf("%d ", ++( *p->y));} 选项：102020|506011|516011|203040
-
name,p->num); printf("%s %d",p->name,p->num);}程序运行后的输出结果是( )。选项： A:SunDan 20042; B:SunDan 20044; C:LiSiGuo 20042; D:YangSan 20041">12.有以下程序：#include
#include struct STU { char name[10]; int num;};void f(char *name, int num);void f(char *name, int num){ struct STU s[2]={{"SunDan",20044},{"Penghua",20045}}; num=s[0].num; strcpy(name,s[0].name);}void main(){ struct STU s[2]={{"YangSan",20041},{"LiSiGao",20042}},*p; p=&s[1]; f(p->name,p->num); printf("%s %d",p->name,p->num);}程序运行后的输出结果是( )。选项： A:SunDan 20042; B:SunDan 20044; C:LiSiGuo 20042; D:YangSan 20041 -
x *(p->y));}A、60B、80C、100D、120">13.以下程序的输出是_______。(参考代码:XT_12_01_03.c)#include
struct st{ int x;int *y;} *p;int dt[4]={ 10,20,30,40 };struct st aa[4]={ 50,&dt[0],60,&dt[1],70,&dt[2],80,&dt[3]};int main( ){p=aa 2;printf("%d",p->x *(p->y));}A、60B、80C、100D、120 - name, p->num); printf("%s%d\n", p->name, p->num); }选项： A:SunDan 20042; B:SunDan 20044; C:LiSiGuo 20042; D:YangSan 20041">14.下列程序的输出结果是 struct STU { char name[10]; int num; }; void f(char *name, int num) { struct STU s[2]={{"SunDan", 20044}, {"Penghua", 20045}}; num=s[0].num; strcpy(name, s[0].name); } int main(void) { struct STU s[2]={{"YangSan", 20041},{"LiSiGuo", 20042}}, *p; p=&s[1]; f(p->name, p->num); printf("%s%d\n", p->name, p->num); }选项： A:SunDan 20042; B:SunDan 20044; C:LiSiGuo 20042; D:YangSan 20041
- name, p->num); printf("%s %d\n", p->name, p->num);} 程序运行后的输出结果是______。选项： A:SunDan 20042 ; B:SunDan 20044; C:LiSiGuo 20042; D:YangSan 20041">15.有以下程序：#include "stdio.h" #include "string.h"struct STU { char name[10]; int num; }; void f(char *name, int num){ struct STU s[2]={{"SunDan",20044},{"Penghua",20045}}; num = s[0].num; strcpy(name, s[0].name);}void main(){ struct STU s[2]={{"YangSan",20041},{"LiSiGuo",20042}},*p; p=&s[1]; f(p->name, p->num); printf("%s %d\n", p->name, p->num);} 程序运行后的输出结果是______。选项： A:SunDan 20042 ; B:SunDan 20044; C:LiSiGuo 20042; D:YangSan 20041
-
x); printf("%d ",(++p)->x); printf("%d\n",++(*（p->y)）);}选项： A:10 20 20; B:50 60 21; C:51 60 21; D:60 70 31">16.以下程序的输出结果是（）。#include
struct st{int x;int *y;}*p;int dt[4]={10,20,30,40};struct st aa[4]={50,&dt[0],60,&dt[1],70,&dt[2],80,&dt[3]};main(){ p=aa; printf("%d ",++p->x); printf("%d ",(++p)->x); printf("%d\n",++(*（p->y)）);}选项： A:10 20 20; B:50 60 21; C:51 60 21; D:60 70 31 - 17.下面程序代码的输出结果是____。class Employee{}class Manager extends Employee{}class Secretary extends Employee{}class Programmer extends Employee{}public class Test{public static void show(Employee e){if(e instanceof Manager)System.out.println("He is a manager.");else if(e instanceof Secretary)System.out.println("He is a secretary.");else if(e instanceof Programmer)System.out.println("He is a programmer.");}public static void main(String[] args){Manager m = new Manager();Secretary s = new Secretary();Programmer p = new Programmer();show(m);show(s);show(p);}}
-
}
public void printThat(int x,int y){
this.x = x;
this.y = y;
System.out.println("x:" + this.x + " y:" + this.y);
}
}
What is the result?
结果如何?
选项： A:x: 1 y: 2 x：3 y: 4
B:x: 0 y: 0 x: 3 y: 4
C:x: 1 y: 2 x: 0 y: 0
D:x: 0 y: 0 x: 0 y: 0
">18.public class Access {private int x = 0;
private int y = 0;
public static void main(String] args) {
Access accApp = new Access();
accApp.printThis(1,2);
accApp.printThat(3,4);
}
public void printThis(int x,int y){
x = x;
y = y;
System.out.println("x:" + this.x + " y:" + this.y);
}
public void printThat(int x,int y){
this.x = x;
this.y = y;
System.out.println("x:" + this.x + " y:" + this.y);
}
}
What is the result?
结果如何?
选项： A:x: 1 y: 2 x：3 y: 4
B:x: 0 y: 0 x: 3 y: 4
C:x: 1 y: 2 x: 0 y: 0
D:x: 0 y: 0 x: 0 y: 0
